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標題: 關于單片機LCD顯示程序，頻率計算問題 [打印本頁]

作者: xnxin 時間: 2019-5-13 09:54
標題: 關于單片機LCD顯示程序，頻率計算問題
void main()
{
      Init_Timer1();
      LCD_Init();
      LCD_Clear();
      LCD_Write_String(0,0,"  Capacitance ");
      LCD_Write_String(0,1,"Cap:       UF");
                     while(1)
                     {
                        if(k1==0){TR0=1;TR1=1;}
                        if(k2==0){asd=0;}
                        if(asd>1000000)
                        {LCD_Write_Char(5,1,q1[asd/100000000]);
                        LCD_Write_Char(6,1,q1[asd%100000000/10000000]);
                        LCD_Write_Char(7,1,q1[asd%10000000/1000000]);
                        LCD_Write_Char(8,1,'.');
                        LCD_Write_Char(9,1,q1[asd%1000000/100000]);
                        LCD_Write_Char(10,1,q1[asd%100000/10000]);
                        LCD_Write_Char(11,1,q1[asd%10000/1000]);
                        LCD_Write_Char(14,1,'U');
                        LCD_Write_Char(15,1,'F');}
                        else
                        {
                        LCD_Write_Char(5,1,q1[asd%1000000/100000]);
                        LCD_Write_Char(6,1,q1[asd%100000/10000]);
                        LCD_Write_Char(7,1,q1[asd%10000/1000]);
                        LCD_Write_Char(8,1,'.');
                        LCD_Write_Char(9,1,q1[asd%1000/100]);
                        LCD_Write_Char(10,1,q1[asd%100/10]);
                        LCD_Write_Char(11,1,q1[asd%10]);
                        LCD_Write_Char(14,1,'N');
                        LCD_Write_Char(15,1,'F');
                        }
                     }
   }

void t0()  interrupt  1       using 1
{
         TH0=(65536-50000)/256;//重新賦值 10ms
   TL0=(65536-50000)%256;                //1us
      i++;
      if(i==60) //使用三秒鐘采集
      {i=0;
            num=num1*65535+TH1*256+TL1;
         asd=470000000/num*3;
         TR0=0;TR1=0;
         TH0=(65536-50000)/256;//重新賦值 10ms
   TL0=(65536-50000)%256;                //1us
         num1=TH1=TL1=0;
      }
}
void Timer1_isr(void) interrupt 3
{
TH1=0x00;             //重新給定初值
TL1=0x00;
num1++;

}

下面這三個程序分別是什么意思？
LCD_Write_Char(5,1,q1[asd/100000000]);
num=num1*65535+TH1*256+TL1；
asd=470000000/num*3;

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